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mysql嵌套查询

select SKTNO,SUM(XSJE) XSJE FROM XSJL查询每个收款台的总销售金额.

select yr_student_info.name from yr_student_info where yr_student_info.school_id in (select yr_school_info.id from yr_school_info where yr_school_info.province='上海' and yr_school_info.city='上海')

sql语句里有嵌套查询,如:select sname from student where sno inselect sno from sc where cno='2';这样得查询可以实现一条指令对两个表操作可在php里我用这个命令来对mysql操作时显示sql语句错误!!不支持,mysql不支持嵌套查询,不

SELECT * FROM tb_login WHERE userid NOT IN (SELECT userid FROM tb_login LIMIT 5) LIMIT 4这样吧

你的sql语句中 的 from 和 to 与sql保留关键词 有冲突.select a.train_no, a.sequ_no t_from , b.sequ_no t_to from (select * from aa where st_name= "xxx" ) as a , (select * from aa where st_name= "xx") as b where a.train_no = b.train_no and a.sequ_no 评论0 0 0

C.这是我的答案.首先A、B两个选项可以优先排除,为什么呢?因为A、B两项只是对记录进行说明,无实在意义.然后就是排除D,既然是嵌套子查询自然会有一些限定条件(如:where子句),若真的没有,那么结果的记录个数才会出现D选项的那种情况,所以,我认为,C是正确答案.希望能帮助你.

select a.id,a.hour from (select id,hour(time) as hour from table) a group by a.hour 不知道对不对 呵呵 感觉这样应该可以

1、说明:复制表(只复制结构,源表名:a 新表名:b) (Access可用) 法一:select * into b from a where 1<>1(仅用于SQlServer) 法二:select top 0 * into b from a2、说明:拷贝表(拷贝数据,源表名:a 目标表名:b) (Access可用) insert

select a.TerminalName, a.Capability,c.OrganIDfrom t_terminal a,t_vehicleorgan b,t_userorgan cwhere a.VehicleID=b.VehicleID and b.OrganID =c.OrganID and c.UserID = ?这样试试,最后的userid=?那自己输入一个值

单引号问题吧,你的mysql配置不支持这种写法 'group' ,单引号去掉吧.

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